Question

Phân tích đa thức thành nhân tử:

a. \(-25x^6-y^8+10x^3y^4\)

b. \(2x^2-2y^2-6x-6y\)

c. \(x^3+3x^2-3x-1\)

Answer 1

c) x^3+3x^2-3x-1=(x^3-1)+(3x^2-3x)=(x-1)(x^2+x+1)+3x(x-1)=(x-1)(x^2+4x+1)

Answer 2

\(-25x^6-y^8+10x^3y^4=-\left(5x^3\right)^2-\left(y^4\right)^2+10x^3y^4=-[5x^3-10x^34^4+y^{^{ }4}]=-\left(5y^3-y^4\right)\)

Answer 3

b) 2x^2-2y^2-6x-6y=2(x^2-y^2)-6(x+y)=2(x+y)(x-y)-6(x+y)=2(x+y)(x-y-6)

Answer 4

−25x6−y⁸10x³y⁴=−(5x³)²−(y⁴)²+10x³y⁴=−[(5x³)²−10x³y⁴+(y⁴)² ]=−(5y³−y⁴)²