Question

giúp nha mb

c1. phân tích đa thức thành nhân tử

a, x^2+2x+1

b, x^2-xy+5x-5y

c2, thực hiện phép tính sau:

a, 2x+6/3x^2-x: x^2+3x/1-3x

b, (4x^4y^2+6x^2y^3-12x^2y):3x^2y

Answer 1

Câu 1 :

a) \(x^2+2x+1=\left(x+1\right)^2\)

b) \(x^2-xy+5x-5y=\left(x^2-xy\right)+\left(5x-5y\right)=x\left(x-y\right)+5\left(x-y\right)=\left(x-y\right)\left(x+5\right)\)

Câu 2 :

b) ( \(4x^4y^2+6x^2y^3-12x^2y\) ) : 3x²y

= \(\dfrac{4}{3}x^2y+2y^2-4\)

\(a,\dfrac{2x+6}{3x^2-x}:\dfrac{x^2+3x}{1-3x}=\dfrac{2\left(x+3\right)}{x\left(3x-1\right)}:\left(-\dfrac{x\left(x+3\right)}{\left(3x-1\right)}\right)=\dfrac{2\left(x+3\right)}{x\left(3x-1\right)}.\left(-\dfrac{\left(3x-1\right)}{x\left(x+3\right)}\right)=\dfrac{2\left(x+3\right).\left(-x\left(3x-1\right)\right)}{x\left(3x-1\right).x\left(x+3\right)}=\dfrac{-2}{x}\)