Ta có: \(\widehat{O_2}+\widehat{O_3}=180^o\left(KB\right)\)\(\Leftrightarrow\widehat{O_2}=180^O-\widehat{O_3}\)
\(\Rightarrow360^o-2\widehat{O_3}-3\widehat{O_3}=60^o\)
\(\Leftrightarrow\widehat{O_3}=\widehat{O_1}\)(ĐĐ)\(=60^o\)
\(\Rightarrow\widehat{O_2}=\widehat{O_4}=180^o-60^o=120^o\)