Câu 16:
PTHH: \(Cl_2+2NaOH\rightarrow NaCl+NaClO+H_2O\)
Ta có: \(\left\{{}\begin{matrix}n_{Cl_2}=\dfrac{33,6}{22,4}=1,5\left(mol\right)\\n_{NaOH}=\dfrac{600\cdot20\%}{40}=3\left(mol\right)\end{matrix}\right.\) \(\Rightarrow\) 2 chất p/ứ hết
Mặt khác: \(m_{Cl_2}=1,5\cdot71=106,5\left(g\right)\)
\(\Rightarrow m_{nướcjaven}=m_{Cl_2}+m_{ddNaOH}=706,5\left(g\right)\)
Câu 21:
PTHH: \(H_2SO_{4\left(đ\right)}+CaF_2\rightarrow CaSO_4+2HF\)
Ta có: \(n_{HF}=\dfrac{250\cdot40\%}{20}=5\left(kmol\right)\)
\(\Rightarrow n_{CaF_2}=2,5\left(kmol\right)\) \(\Rightarrow m_{CaF_2}=2,5\cdot78=195\left(kg\right)\)