\(\Leftrightarrow\left(x-3\right)\left[\left(x-3\right)^2-\left(x^2+3x+9\right)\right]+6\left(x+1\right)^2=15\)
\(\Leftrightarrow-9x\left(x-3\right)+6\left(x^2+2x+1\right)-15=0\)
\(\Leftrightarrow-9x^2+27x+6x^2+12x+6-15=0\)
\(\Leftrightarrow-3x^2+41x-9=0\)
Bạn coi lại đề, nghiệm rất xấu