MÌNH CẢM MƠM RẤT NHÌU
\(x-y+2xy=3\)
\(\Rightarrow x+2xy-y=3\)
\(\Rightarrow x\left(1+2y\right)-y=3\)
\(\Rightarrow2x\left(1+2y\right)-2y=6\)
\(\Rightarrow2x\left(1+2y\right)-2y-1=5\)
\(\Rightarrow2x\left(2y+1\right)-\left(2y+1\right)=5\)
\(\Rightarrow\left(2x-1\right)\left(2y+1\right)=5\)
Ta có bảng sau: \(\left(x,y\in Z\right)\)
| \(2x-1\) | 1 | 5 | -1 | -5 |
| \(2y+1\) | 5 | 1 | -5 | -1 |
| x | 1 | 3 | 0 | -2 |
| y | 2 | 0 | -3 | -1 |
Vậy cặp số \(\left(x;y\right)\) là \(\left(1;2\right);\left(3;0\right);\left(0;-3\right);\left(-2;-1\right)\)
\(x-y+2xy=3\)
\(\Leftrightarrow2x-2y+4xy=6\)
\(\Leftrightarrow2x-1+4xy-2y=5\)
\(\Leftrightarrow\left(2x-1\right)+2y\left(2x-1\right)=5\)
\(\Leftrightarrow\left(2x-1\right)\left(2y+1\right)=5\)
Lập bảng:
