Câu hỏi của Omega Neo

Question

Let the rectangle ABCD, AB=2/3BC and the area is 24cm2. What is the perimeter of the rectangle ABCD

Nguyễn Việt Lâm · Accepted Answer

We have $S_{ABCD}=AB.BC=\frac{2}{3}BC.BC=\frac{2}{3}BC^2$

So $\frac{2}{3}BC^2=24\Rightarrow BC^2=36\Rightarrow BC=6\Rightarrow AB=4$ (cm)

$\Rightarrow$ The perimeter of ABCD is $2.\left(4+6\right)=20\left(cm\right)$Câu trả lời: We have $S_{ABCD}=AB.BC=\frac{2}{3}BC.BC=\frac{2}{3}BC^2$

So $\frac{2}{3}BC^2=24\Rightarrow BC^2=36\Rightarrow BC=6\Rightarrow AB=4$ (cm)

$\Rightarrow$ The perimeter of ABCD is $2.\left(4+6\right)=20\left(cm\right)$

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