\(\left(x-3\right)^2=\left(3x-2\right)^2\)
\(\Rightarrow x-3=3x-2\)
\(\Rightarrow x-3x=-2+3\)
\(\Rightarrow-2x=1\)
\(\Rightarrow x=-\dfrac{1}{2}\)
\(\left(2x+7\right)^2=\left(x+3\right)^2\)
\(\Rightarrow2x+7=x+3\)
\(\Rightarrow2x-x=3-7\)
\(\Rightarrow x=-4\)
a: (3x-2)^2=(x-3)^2
=>3x-2=x-3 hoặc 3x-2=3-x
=>2x=-1 hoặc 4x=5
=>x=5/4 hoặc x=-1/2
b: (2x+7)^2=(x+3)^2
=>2x+7=x+3 hoặc 2x+7=-x-3
=>x=-4 hoặc x=-10/3