Question

(\(\left(\sqrt{12}-6\sqrt{3}+\sqrt{24}\right)\cdot\sqrt{6}-\left(5\sqrt{\dfrac{1}{2}}+12\right)=-14.5\sqrt{2}\)

Answer 1

Sửa đề: \(\left(\sqrt{12}-6\sqrt{3}+\sqrt{24}\right)\cdot\sqrt{6}\cdot\left(5\sqrt{\dfrac{1}{2}}+12\right)\)

\(=\left(2\sqrt{3}-6\sqrt{3}+2\sqrt{6}\right)\cdot\sqrt{6}\cdot\left(\dfrac{5}{2}\sqrt{2}+12\right)\)

\(=\left(-4\sqrt{3}+2\sqrt{6}\right)\cdot\left(\dfrac{5}{2}\sqrt{12}+12\sqrt{6}\right)\)

\(=\left(-4\sqrt{3}+2\sqrt{6}\right)\left(5\sqrt{3}+12\sqrt{6}\right)\)

\(=-60-144\sqrt{2}+30\sqrt{2}+144\)

\(=84-114\sqrt{2}\)