\(\left(\dfrac{1}{2}x-\dfrac{2}{3}\right)-\left(\dfrac{1}{3}x-1\right)=\left(x-3\right)-\left(x-1\right)\)
\(\Leftrightarrow\dfrac{1}{2}x-\dfrac{2}{3}-\dfrac{1}{3}x+1=x-3-x+1\)
\(\Leftrightarrow\dfrac{1}{2}x-\dfrac{2}{3}-\dfrac{1}{3}x=-3\)
\(\Leftrightarrow\dfrac{x}{6}-\dfrac{2}{3}=-3\)
\(\Leftrightarrow x-4=-18\)
\(\Leftrightarrow x=-18+4\)
\(\Leftrightarrow x=-14\)
Vậy \(x=-14\)
Tìm x biết :\(\dfrac{1}{x\left(x+1\right)}\) +\(\dfrac{1}{\left(x+1\right)\left(x+2\right)}\) \(\dfrac{1}{\left(x+2\right)\left(x+3\right)}\) -\(\dfrac{1}{x}\) =\(\dfrac{1}{2010}\)
e) \(\dfrac{3}{3x}-\dfrac{3}{12}=\dfrac{4}{5}-\left(\dfrac{7}{x}-2\right)\)
f) \(\dfrac{1}{x-1}+\dfrac{-2}{3}\left(\dfrac{3}{4}-\dfrac{6}{5}\right)=\dfrac{5}{2-2x}\)
c )\(\dfrac{x}{2}-\left(\dfrac{3x}{5}-\dfrac{13}{5}\right)=-\left(\dfrac{7}{5}+\dfrac{7}{10}.x\right)\)
d)\(\dfrac{2x-3}{3}+\dfrac{-3}{2}=\dfrac{5-3x}{6}-\dfrac{1}{3}\)
Tìm x biết
a. \(x:\left(\dfrac{-3}{5}\right)^2=\dfrac{-3}{5}\)
b.\(\left(\dfrac{-1}{3}\right)^3.x=\dfrac{1}{81}\)
c.\(\left(2x^2\right)=16\)
1.Tìm x
a) \(1\dfrac{4}{5}=-0,15-x\)
b) \(-\dfrac{4}{7}-x=\dfrac{3}{5}-2x\)
c) \(\left(\dfrac{3}{8}-\dfrac{1}{5}\right)+\left(\dfrac{5}{8}-x\right)=\dfrac{1}{5}\)
Bài 8:
b)\(\left(\dfrac{-4}{3}\right)+\left(\dfrac{-2}{5}\right)+\left(\dfrac{-3}{2}\right)\)
c) \(\dfrac{4}{5}-\left(\dfrac{-2}{7}\right)-\dfrac{-7}{10}\)
d) \(\dfrac{2}{3}-\left[\left(\dfrac{-7}{4}\right)-\left(\dfrac{1}{2}+\dfrac{3}{8}\right)\right]\)
Tìm x để các biểu thức sau là số hữu tỉ âm :
A = \(\dfrac{\left(x+3\right).\left(4x+5\right)}{\left(20-4x\right).\left(2.x\right)}\)
B= \(\dfrac{\left(x+1\right).\left(7-2x\right)}{\left(5x-4\right).\left(10-2x\right)}\)
\(\left(1-\dfrac{1}{2}\right)\left(1-\dfrac{1}{3}\right)\left(1-\dfrac{1}{4}\right)...\left(1-\dfrac{1}{2022}\right)\)
a\(\left(4x-5\right)\left(3x+2\right)=0\)
b\(\dfrac{x+1}{2016}+\dfrac{x+2}{2015}=\dfrac{x+3}{2014}+\dfrac{x+4}{2013}\)
