Chương 3: PHƯƠNG TRÌNH, HỆ PHƯƠNG TRÌNH
Các câu hỏi tương tự
giải hệ phương trình
a,left{{}begin{matrix}dfrac{2}{x}+dfrac{3}{y}5dfrac{1}{x}-dfrac{4}{y}-3end{matrix}right.
b,left{{}begin{matrix}dfrac{12}{x-3}-dfrac{5}{y+2}63dfrac{8}{x-3}+dfrac{15}{y+2}-13end{matrix}right.
c,left{{}begin{matrix}dfrac{4}{x+2}-dfrac{1}{x-2y}1dfrac{20}{x+2y}+dfrac{3}{x-2y}1end{matrix}right.
d,left{{}begin{matrix}left|x-1right|+left|y-2right|2left|x-1right|+y3end{matrix}right.
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giải hệ phương trình
a,\(\left\{{}\begin{matrix}\dfrac{2}{x}+\dfrac{3}{y}=5\\\dfrac{1}{x}-\dfrac{4}{y}=-3\end{matrix}\right.\)
b,\(\left\{{}\begin{matrix}\dfrac{12}{x-3}-\dfrac{5}{y+2}=63\\\dfrac{8}{x-3}+\dfrac{15}{y+2}=-13\end{matrix}\right.\)
c,\(\left\{{}\begin{matrix}\dfrac{4}{x+2}-\dfrac{1}{x-2y}=1\\\dfrac{20}{x+2y}+\dfrac{3}{x-2y}=1\end{matrix}\right.\)
d,\(\left\{{}\begin{matrix}\left|x-1\right|+\left|y-2\right|=2\\\left|x-1\right|+y=3\end{matrix}\right.\)
\(\left\{{}\begin{matrix}x^2+y^2=\dfrac{1}{2}\\x^3+3xy^2=\dfrac{1}{2}\end{matrix}\right.\)
\(\left\{{}\begin{matrix}\left(1+x^2\right)^2\left(1+\dfrac{1}{y^4}\right)=8\\\left(1+y^2\right)^2\left(1+\dfrac{1}{x^4}\right)=8\end{matrix}\right.\)
Em cảm ơn ạ !!!
Giai pt: \(\left\{{}\begin{matrix}\left(\dfrac{x}{y}+\dfrac{y}{x}\right)\left(x+y\right)=15\\\left(\dfrac{x^2}{y^2}+\dfrac{y^2}{x^2}\right)\left(x^2+y^2\right)=85\end{matrix}\right.\)
GHPT: \(\left\{{}\begin{matrix}2x+\dfrac{1}{x+y}+\dfrac{1}{x-y}=\dfrac{16}{3}\\2\left(x^2+y^2\right)+\dfrac{1}{\left(x+y\right)^2}+\dfrac{1}{\left(x-y\right)^2}=\dfrac{100}{9}\end{matrix}\right.\)
giải giúp mik bt này vs mn!
1)left{{}begin{matrix}2x^2+y^2+x3left(xy+1right)+2ydfrac{2}{3+sqrt{2x-y}}+dfrac{2}{3+sqrt{4-5x}}dfrac{9}{2x-y+9}end{matrix}right.
2)left{{}begin{matrix}left(x+3y+1right)sqrt{2xy+2y}yleft(3x+4y+3right)left(sqrt{x+3}-sqrt{2y-2}right)left(x-3+sqrt{x^2+x+2y-4}right)4end{matrix}right.
3)left{{}begin{matrix}x-dfrac{1}{x}y-dfrac{1}{y}2yx^3+1end{matrix}right.
4)left{{}begin{matrix}sqrt{2x-3}left(y^2+2011right)left(5-yright)+sqrt{y}yleft(y-x+2right)3x+3end{matrix}right.
5...
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giải giúp mik bt này vs mn!
1)\(\left\{{}\begin{matrix}2x^2+y^2+x=3\left(xy+1\right)+2y\\\dfrac{2}{3+\sqrt{2x-y}}+\dfrac{2}{3+\sqrt{4-5x}}=\dfrac{9}{2x-y+9}\end{matrix}\right.\)
2)\(\left\{{}\begin{matrix}\left(x+3y+1\right)\sqrt{2xy+2y}=y\left(3x+4y+3\right)\\\left(\sqrt{x+3}-\sqrt{2y-2}\right)\left(x-3+\sqrt{x^2+x+2y-4}\right)=4\end{matrix}\right.\)
3)\(\left\{{}\begin{matrix}x-\dfrac{1}{x}=y-\dfrac{1}{y}\\2y=x^3+1\end{matrix}\right.\)
4)\(\left\{{}\begin{matrix}\sqrt{2x-3}=\left(y^2+2011\right)\left(5-y\right)+\sqrt{y}\\y\left(y-x+2\right)=3x+3\end{matrix}\right.\)
5)\(\left\{{}\begin{matrix}x^3+2x^2=x^2y+2xy\\2\sqrt{x^2-2y-1}+\sqrt[3]{y^3-14=x-2}\end{matrix}\right.\)
giải hpt \(\left\{{}\begin{matrix}\dfrac{1-xy}{x\left(1+y^2\right)}=\dfrac{2}{5}\\\dfrac{1-xy}{y\left(1+x^2\right)}=\dfrac{1}{2}\end{matrix}\right.\)
giải hpt:
\(\left\{{}\begin{matrix}3\left(y^2+x^2\right)+\dfrac{1}{\left(x-y\right)^2}=2\left(10-xy\right)\\2x+\dfrac{1}{x-y}=5\end{matrix}\right.\)
Giải HPT:
1. \(\left\{{}\begin{matrix}x^2+y^2+\dfrac{2xy}{x+y}=1\\\sqrt{x+y}=x^2-y\end{matrix}\right.\)
2. \(\left\{{}\begin{matrix}\dfrac{1}{\sqrt{x+2}}+\dfrac{1}{\sqrt{y-1}}=\dfrac{2}{\sqrt{x+y}}\\x^2+y^2+4xy-4x+2y-5=0\end{matrix}\right.\)
GHPT sau: \(\left\{{}\begin{matrix}\dfrac{25}{9}+\sqrt{9x^2-4}=\dfrac{1}{9}\left(\dfrac{2}{x}+\dfrac{18x}{y^2-2y+2}+25y\right)\\7x^3+y^3+3xy\left(x-y\right)-12x^2+6x=1\end{matrix}\right.\)