\(\sqrt{2}\left(\sqrt{3}+1\right)\)
\(=\sqrt{6}+\sqrt{2}\)
Ta có: \(\left(\sqrt{6}+\sqrt{2}\right)^2=8+4\sqrt{3}\)
Và: \(\left(\sqrt{3}+2\right)^2=7+4\sqrt{3}\)
Ta thấy: \(8+4\sqrt{3}>7+4\sqrt{3}\)
Hay: \(\sqrt{2}\left(\sqrt{3}+1\right)>\sqrt{3}+2\) (đpcm)