ta có : \(4a-3b⋮19\Leftrightarrow20a-15b⋮19\Leftrightarrow4\left(5a+b\right)-19b⋮19\)
\(\Rightarrow5a+b⋮19\left(đpcm\right)\)
bài còn lại lm tương tự nha
2. \(4a+3b⋮13\Leftrightarrow7\left(4a+3b\right)⋮13\Leftrightarrow28a+21b⋮13\Leftrightarrow28a+21b-13b⋮13\Leftrightarrow28a+8b⋮13\Leftrightarrow4\left(7a+2b\right)⋮13\Leftrightarrow7a+2b⋮13\)
Vậy \(4a+3b⋮13\Leftrightarrow7a+2b⋮13\)