I. Tính:
1) \(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}\)
\(=\dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+\dfrac{1}{4.5}+\dfrac{1}{5.6}\)
\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}\)
\(=1-\dfrac{1}{6}\)
\(=\dfrac{5}{6}\)
2) \(\dfrac{2}{15}+\dfrac{2}{35}+\dfrac{2}{63}+\dfrac{2}{99}+\dfrac{2}{143}\)
\(=\dfrac{2}{3.5}+\dfrac{2}{5.7}+\dfrac{2}{7.9}+\dfrac{2}{9.11}+\dfrac{2}{11.13}\)
\(=\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{13}\)
\(=\dfrac{1}{3}-\dfrac{1}{13}\)
\(=\dfrac{13}{39}-\dfrac{3}{39}=\dfrac{10}{39}\)
II. Tìm x:
\(1\dfrac{3}{5}+\left(\dfrac{\dfrac{2}{171}}{\dfrac{5}{171}}+\dfrac{\dfrac{2}{373}}{\dfrac{5}{373}}\right)x=\dfrac{16}{5}\)
\(\dfrac{8}{5}+\left[\dfrac{2\left(\dfrac{1}{171}+\dfrac{1}{373}\right)}{5\left(\dfrac{1}{171}+\dfrac{1}{373}\right)}\right]x=\dfrac{16}{5}\)
\(\dfrac{8}{5}+\dfrac{2}{5}x=\dfrac{16}{5}\)
\(\dfrac{2}{5}x=\dfrac{16}{5}-\dfrac{8}{5}\)
\(\dfrac{2}{5}x=\dfrac{8}{5}\)
\(x=\dfrac{8}{5}:\dfrac{2}{5}\)
\(x=4\)