Question

I. Tính

1) (1+\(\dfrac{2}{3}\)-\(\dfrac{1}{4}\)). 0,8- \(\dfrac{3}{4}\))\(^2\)

2) (2\(^2\): \(\dfrac{4}{3}\)-\(\dfrac{1}{2}\)).\(\dfrac{6}{5}\)-17

3)24\(\dfrac{1}{7}\):\(\dfrac{-3}{5}\)-33\(\dfrac{1}{7}\):\(\dfrac{-3}{5}\)

Answer 1

1) (1+\( \dfrac{2}{3}\)-\(\dfrac{1}{4}\)). 0,8-\(\dfrac{3}{4}\))²

=( \(\dfrac{17}{12}\).0,8-\(\dfrac{3}{4}\))²

=(\(\dfrac{17}{15}\)-\(\dfrac{3}{4}\))²

=( \(\dfrac{23}{60}\))²

^{= \(\dfrac{529}{3600}\)}

Answer 2

2) \(\dfrac{5}{2}\).\(\dfrac{6}{5}\)-17

=3-17=(-14)

3) (\(24\dfrac{1}{7}\)-\(33\dfrac{1}{7}\)):\(\dfrac{-3}{5}\)

=-9:(\(\dfrac{-3}{5}\))=15