Bài 1:
a/ \(5^2.3-16:2^2\)\(=25.3-16:4=75-4=71\)
b/\(3.5^2-40:2^3=3.25-40:8=75-5=70\)
c/\(4.5^3-81.3^2=4.125-81.9=500-729=\)\(-229\)
d/\(2^3.15-\left[115-\left(12-5\right)^2\right]\)\(=8.115-\left[115-7^2\right]\)\(=920+115+49=1084\)
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a/ 52.3−16:2252.3−16:22=25.3−16:4=75−4=71=25.3−16:4=75−4=71
b/3.52−40:23=3.25−40:8=75−5=703.52−40:23=3.25−40:8=75−5=70
c/4.53−81.32=4.125−81.9=500−729=4.53−81.32=4.125−81.9=500−729=−229−229
d/23.15−[115−(12−5)2]23.15−[115−(12−5)2]=8.115−[115−72]=8.115−[115−72]=920+115+49=1084
\(\)a, \(5^2.3-16:2^2\)
= \(25.3-16:4\)
= \(75-4\)
= \(71\)
b, \(3.5^2-40:2^3\)
= \(3.25-40:8\)
= \(75-5\)
= \(70\)
c, \(4.5^3-81.3^2\)
= \(4.125-81.9\)
= \(500-729\)
= \(-229\)\(\)
b, \(2^3.15-\left[115-\left(12-5\right)^2\right]\)
= \(8.15-\left[115-49\right]\)
= \(120-66\)
= \(54\)