Question

hòa tan 8g NaCl vào 152g nước . tính khối lượng dung dịch thu đc

Answer 1

tk

b) mdd = 8+152=160 (g)

Answer 2

\(m_{dd}=8+152=160\left(g\right)\)

Answer 3

mdd = mct + mdm = mNaCl + mH2O = 8 + 152 = 160 (g)

Answer 4

\(n_{NaCl}=\dfrac{m_{NaCl}}{M_{NaCl}}=\dfrac{8}{58,5}=\dfrac{16}{117}mol\)

\(n_{H_2O}=\dfrac{m_{H_2O}}{M_{H_2O}}=\dfrac{152}{18}=\dfrac{76}{9}mol\)

\(2NaCl+2H_2O\rightarrow2NaOH+Cl_2+H_2\)

    2            2                2             1      1       ( mol )

   \(\dfrac{16}{117}\)   <  \(\dfrac{76}{9}\)                                        ( mol )

    \(\dfrac{16}{117}\)                        \(\dfrac{16}{117}\)             ( mol )

\(m_{NaOH}=n_{NaOH}.M=\dfrac{16}{117}.40=\dfrac{640}{117}g\)