Question

Hãy tính giá trị biểu thức sau :

a, A = 120 : {60 : [( 3² + 4² ) - 5 ]}

b, B = 1/2 + 1/3 - 1/6

c, C = l 4 - 6 l + 2

d, D = 2² + 2³ + 3² + 3³ - 48

giúp mình vs , please :(((((

Answer 1

a) A = 120 : {60 : [(\(3^2+4^2\)) - 5]}

=120:[60:(25-5)]

=120 : (60 : 20)

= 120:3 = 40

b)B=\(\dfrac{1}{2}+\dfrac{1}{3}-\dfrac{1}{6}\)

=\(\dfrac{3.6}{2.3.6}+\dfrac{2.6}{2.3.6}-\dfrac{2.3}{2.3.6}\)

=\(\dfrac{18+12-6}{36}=\dfrac{24}{36}=\dfrac{2}{3}\)

c) C = |4 - 6| + 2

=| -2 | +2

= 2 + 2 = 4

d) D= \(2^2+2^3+3^2+3^3-48\)

= \(2^2+2^3+3^2+3^3-2^4.3\)

= (\(2^2+2^3-2^4.3\)) +\(\left(3^2+3^3\right)\)

= \(2^2\left(1+2-2^2.3\right)+3^2\left(1+3\right)\)

= \(4\left(-9\right)+36\)= -36 + 36 =0