\(a,\text{Ta có:}AB=AC\left(gt\right)\Rightarrow\Delta ABC\text{ cân tại A}\Rightarrow\widehat{ABC}=\widehat{ACB}\left(\text{tính chất tam giác cân}\right)\)
\(\text{Xét }\Delta ABC\text{ có: }\widehat{BAC}+\widehat{ABC}+\widehat{ACB}=180^o\left(\text{tổng 3 góc trong }\Delta\right)\)
\(\text{Mà }\widehat{ACB}=\widehat{ABC}\left(cmt\right),\widehat{BAC}=145^o\left(gt\right)\)
\(\Leftrightarrow145^o+2\widehat{ABC}=180^o\)
\(\)\(\Leftrightarrow2\widehat{ABC}=35^o\)
\(\Leftrightarrow\widehat{ABC}=17,5^o\)
\(\text{Vậy }\widehat{ABC}=17,5^o\)
\(b,\text{Ta có:}AB=AC\left(gt\right)\Rightarrow\Delta ABC\text{ cân tại A}\Rightarrow\widehat{ABC}=\widehat{ACB}\left(\text{tính chất tam giác cân}\right)\)
\(\text{Xét }\Delta ABC\text{ có: }\widehat{BAC}+\widehat{ABC}+\widehat{ACB}=180^o\left(\text{tổng 3 góc trong }\Delta\right)\)
\(\text{Mà }\widehat{ACB}=\widehat{ABC}\left(cmt\right),\widehat{BAC}=100^o\left(gt\right)\)
\(\Leftrightarrow100^o+2\widehat{ABC}=180^o\)
\(\Leftrightarrow2\widehat{ABC}=80^o\)
\(\Leftrightarrow2\widehat{ABC}=80^o\)
\(\Leftrightarrow\widehat{ABC}=40^o\)
\(\text{Vậy }\widehat{ABC}=40^o\)