Question

giúp vs ạ 

Answer 1

\(-4\dfrac{2}{3}\left(\dfrac{1}{2}-\dfrac{1}{6}\right)=-\dfrac{14}{3}\left(\dfrac{1}{2}-\dfrac{1}{6}\right)=-\dfrac{7}{3}+\dfrac{7}{9}=-\dfrac{14}{9}\)

\(\dfrac{2}{3}\left(\dfrac{1}{3}-\dfrac{1}{2}-\dfrac{3}{4}\right)=\dfrac{2}{9}-\dfrac{1}{3}-\dfrac{1}{2}=-\dfrac{11}{18}\)

\(\Rightarrow-\dfrac{14}{9}\le x\le-\dfrac{11}{18}\\ \Rightarrow x=-1\)

Answer 2

\(\Leftrightarrow\dfrac{-14}{3}.\dfrac{1}{3}< x\le-\dfrac{2}{3}.\dfrac{-11}{12}\)

\(\Leftrightarrow\dfrac{-14}{9}< x\le\dfrac{11}{18}\)

Do \(x\in Z\)

\(\Rightarrow x\in\left\{-1;0\right\}\)