\(\frac{a}{2,5}=\frac{8a}{20}\)
\(\frac{b}{4,5}=\frac{5b}{22,5}\)
mà \(\frac{a}{2,5}=\frac{b}{4,5}\)
=> \(\frac{8a}{20}=\frac{5b}{22,5}\)
Áp dụng tính chất của dãy tỉ số bằng nhau, ta có:
\(\frac{8a}{20}=\frac{5b}{22,5}=\frac{8a-5b}{20-22,5}=\frac{-4}{-2,5}=1,6\)
\(\left[\begin{array}{nghiempt}\frac{8a}{20}=1,6\\\frac{5b}{22,5}=1,6\end{array}\right.\)
\(\left[\begin{array}{nghiempt}8a=1,6\times20\\5b=1,6\times22,5\end{array}\right.\)
\(\left[\begin{array}{nghiempt}8a=32\\5b=36\end{array}\right.\)
\(8a+5b=32+36=68\)