Question

giúp mk vs

a) \(2x-\dfrac{1}{4}=\dfrac{1}{2}\)

b) \(\dfrac{-2}{3}.x+\dfrac{1}{5}=\dfrac{3}{10}\)

Answer 1

a)

\(2x-\dfrac{1}{4}=\dfrac{1}{2}\\ 2x=\dfrac{1}{2}+\dfrac{1}{4}\\ 2x=\dfrac{3}{4}\\ x=\dfrac{3}{4}:2\\ x=\dfrac{3}{8}\)

b)

\(\dfrac{-2}{3}\cdot x+\dfrac{1}{5}=\dfrac{3}{10}\\ \dfrac{-2}{3}x=\dfrac{3}{10}-\dfrac{1}{5}\\ \dfrac{-2}{3}x=\dfrac{1}{10}\\ x=\dfrac{1}{10}:\dfrac{-2}{3}\\ x=\dfrac{-3}{20}\)

Answer 2

a) \(2x-\dfrac{1}{4}=\dfrac{1}{2}\)

\(2x=\dfrac{1}{2}+\dfrac{1}{4}\)

\(2x=\dfrac{4}{8}+\dfrac{2}{8}=\dfrac{6}{8}=\dfrac{3}{4}\)

\(x=\dfrac{3}{4}:2=\dfrac{3}{4}.\dfrac{1}{2}=\dfrac{3}{8}\)

Vậy x = \(\dfrac{3}{8}\)

b) \(\dfrac{-2}{3}.x+\dfrac{1}{5}=\dfrac{3}{10}\)

\(\dfrac{-2}{3}.x=\dfrac{3}{10}-\dfrac{1}{5}\)

\(\dfrac{-2}{3}.x=\dfrac{3}{10}-\dfrac{2}{10}\)

\(\dfrac{-2}{3}.x=\dfrac{1}{10}\)

\(x=\dfrac{1}{10}:\dfrac{-2}{3}=\dfrac{1}{10}.\dfrac{3}{-2}\)

\(x=\dfrac{3}{-20}\)

Vậy x = \(\dfrac{3}{-20}\)

Answer 3

ÔNG LÊ KO GIẢI NỔI MẤY CÂU NÀY HẢ ???