\(\lim\limits_{x\rightarrow3^+}\frac{7x-1}{x-3}=\frac{20}{0}=+\infty\)
\(\lim\limits_{x\rightarrow5^+}\frac{11-2x}{x-5}=\frac{1}{0}=+\infty\)
\(\lim\limits_{x\rightarrow3^-}\frac{-x-3}{3-x}=\frac{-6}{0}=-\infty\)
Tìm các giới hạn sau
a/lim \(\frac{x^2+2x-3}{2x^{2^{ }}-x-1}\) (x-->2)
b/lim\(\frac{2x^3-5x^2-2x-3}{4x^3-13x^2+4x-3}\) (x--->3)
c/lim\(\frac{x^5+1}{x^3+1}\) (x--->-1)
tìm các giới hạn sau:
a; \(\lim\limits_{x\rightarrow1}\frac{2x^4-5x^3+3x^2+1}{3x^4-8x^3+6x^2-1}\)
b; \(\lim\limits_{x\rightarrow1}\frac{x^3-3x^2+2}{x^4-4x+3}\)
c; \(\lim\limits_{x\rightarrow1}\frac{x^3-2x-1}{x^5-2x-1}\)
d; \(\lim\limits_{x\rightarrow-1}\frac{\left(x+2\right)^2-1}{x^2-1}\)
BÀI 3. Tính các giới hạn sau:
a) \(\lim\limits_{x\rightarrow-\infty}\dfrac{2x^3-5x^2+1}{7x^2-x+4}\)
b) \(\lim\limits_{x\rightarrow+\infty}x\sqrt{\dfrac{x^2+2x+3}{3x^4+4x^2-5}}\)
tìm các giới hạn sau:
a, \(\lim\limits_{x\rightarrow0}\frac{\sqrt{1+x^2}-1}{x}\)
b,\(\lim\limits_{x\rightarrow1}\frac{\sqrt[3]{x+7}-\sqrt{5-x^2}}{x-1}\)
c, \(\lim\limits_{x\rightarrow0}\frac{\sqrt[3]{1+x}-\sqrt[3]{1-x}}{x}\)
d, \(\lim\limits_{x\rightarrow2}\frac{\sqrt[3]{4x-2}}{x-2}\)
Tìm các giới hạn sau:
a) \(\lim\limits_{x\rightarrow-1}\frac{\sqrt[3]{x}+1}{2x^2+5x+3}\)
b) \(\lim\limits_{x\rightarrow1}\frac{\sqrt[3]{x^2}-2\sqrt[3]{x}+1}{\left(x-1\right)^2}\)
c)\(\lim\limits_{x\rightarrow1}\frac{\sqrt[4]{x}-1}{x^3+x^2-2}\)
d) \(\lim\limits_{x\rightarrow-2}\frac{\sqrt[3]{2x+12}+x}{x^2+2x}\)
mọi người ơi giúp mình với, mình cảm ơn nhiều ạ :((((
tìm các giới hạn sau:
a, \(\lim\limits_{x\rightarrow1}\frac{x^4-1}{x^3-2x^2+1}\) ( câu a,b chỉ cần thay số vào thôi đúng k ạ nếu là thay số thì k cần trình bày nữa đâu )
b, \(\lim\limits_{x\rightarrow-1}\frac{x^5+1}{x^3+1}\)
c, \(\lim\limits_{x\rightarrow3}\frac{x^3-5x^2+3x+9}{x^4-8x^2-9}\)
d, \(\lim\limits_{x\rightarrow1}\frac{x-5x^5+4x^6}{\left(1-x\right)^2}\)
e, \(\lim\limits_{x\rightarrow1}\frac{x^m-1}{x^n-1}\)
f, \(\lim\limits_{x\rightarrow-2}\frac{x^4-16}{x^3+2x^2}\)
a,\(^{lim}_{x->2}\frac{\sqrt[3]{8x+11}-\sqrt{x+7}}{x^2-3x+2}\)
b, \(^{lim}_{x->0}\frac{2\sqrt{1+x}-\sqrt[3]{8-x}}{x}\)
c, \(^{lim}_{x->1}\frac{\sqrt{5-x^3}-\sqrt[3]{x^2+7}}{x^2-1}\)
d,\(^{lim}_{x->0}\frac{\sqrt{1+2x}.\sqrt[3]{1+4x}-1}{x}\)
e,\(^{lim}_{x->1}\frac{x^4-1}{x^3-2x^2+x}\)
f,\(^{lim}_{x->1}\left(\frac{1}{1-x}-\frac{3}{1-x^3}\right)\)
Tìm các giới hạn sau :
a, lim\(\dfrac{2x^2+x-6}{x^3+8}\) khi x→-2
b, lim\(\dfrac{x^4-x^2-72}{x^2-2x-3}\) khi x→3
c, lim\(\dfrac{x^5+1}{x^3+1}\) khi x→-1
d, lim \(\left(\dfrac{2}{x^2-1}-\dfrac{1}{x-1}\right)\) khi x→1
Tính các giới hạn sau đây :
\(L_1=lim\frac{x^3+3x^2-2x}{x^5+4x}\left(x\rightarrow0\right)\)
\(L_2=lim\frac{x^3-3x+2}{\left(4-2x\right)^3}\left(x\rightarrow+\infty\right)\)
\(L_3=lim\frac{2x^2+3x+1}{x^2+x}\left(x\rightarrow-1\right)\)
\(L_4=lim\frac{x^2-4x+1}{4-x^2}\left(x\rightarrow2\right)\)
\(L_5=lim\frac{\sqrt{x+1}-2}{x-2}\left(x\rightarrow3\right)\)
\(L_6=lim\frac{\sqrt{x+3}-x-1}{x^2-1}\left(x\rightarrow1\right)\)
\(L_7=lim\left(\sqrt{x^2+x+1}-x+1\right)\left(x\rightarrow+\infty\right)\)
\(L_8=lim\left(\sqrt{x^2+x+1}-3x+2\right)\left(x\rightarrow-\infty\right)\)
