Bài 1:
a: \(\dfrac{13\sqrt{2}-4\sqrt{6}}{24-4\sqrt{3}}=\dfrac{\sqrt{2}\left(13-4\sqrt{3}\right)}{4\sqrt{3}\left(2\sqrt{3}-1\right)}=\dfrac{\sqrt{2}\left(2\sqrt{3}-1\right)}{4\sqrt{3}}=\dfrac{\sqrt{6}\left(2\sqrt{3}-1\right)}{12}\)
b: \(\dfrac{\sqrt{3-2\sqrt{2}}}{\sqrt{17-12\sqrt{2}}}=\dfrac{\sqrt{2}-1}{3-2\sqrt{2}}=\sqrt{2}+1\)
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