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Tính bằng cách hợp lí
\(\frac{3}{4}:\frac{22}{9}-\left|-3x+\frac{8}{3}\right|=\frac{3}{4}\)
\(\frac{2\cdot6^9-2^5\cdot18^4}{2^2\cdot6^8}\)
\(139\frac{5}{7}:\frac{2}{3}-138\frac{2}{7}:\sqrt{\frac{4}{9}}\)
\(\left(-\frac{5}{11}:\frac{13}{8}-\frac{5}{11}:\frac{13}{5}\right)+-\frac{1}{33}\)
139\(\frac{5}{7}:\frac{2}{3}\)-\(138\frac{2}{7}:\sqrt{\frac{4}{9}}\)
=139\(\frac{5}{7}:\frac{2}{3}\)-\(138\frac{2}{7}:\frac{2}{3}\)
=(139\(\frac{5}{7}\)-\(138\frac{2}{7}\)):\(\frac{2}{3}\) =\(1\frac{3}{7}\):\(\frac{2}{3}\) =\(\frac{9}{7}.\frac{3}{2}\) =\(\frac{27}{14}\)=\(\frac{2.2^9.3^9-2^5.2^4.3^8}{2.2^8.3^8}\)
=\(\frac{2^{10}.3^9-2^9.3^8}{2^9.3^8}\)
=\(\frac{2^9.3^8.\left(2.3-1\right)}{2^9.3^8}\)
=\(6-1\)
=5