a) \(\left|x\right|=3\dfrac{1}{2}\)
\(\Rightarrow\left|x\right|=\dfrac{7}{2}\)
\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{7}{2}\\x=-\dfrac{7}{2}\end{matrix}\right.\)
b) \(\left|x-1,2\right|=2,8\)
\(\Rightarrow\left[{}\begin{matrix}x-1,2=2,8\\x-1,2=-2,8\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=4\\x=-1,6\end{matrix}\right.\)
\(a,\left|x\right|=3\dfrac{1}{2}\)
\(\Rightarrow x=\left[{}\begin{matrix}3\dfrac{1}{2}\\-3\dfrac{1}{2}\end{matrix}\right.\)
\(b,\left|x-1,2\right|=2,8\\ \Rightarrow\left[{}\begin{matrix}x-1,2=2,8\\x-1,2=-2,8\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2,8+1,2=4\\x=-2,8+1,2=-1,6\end{matrix}\right.\)
Vậy \(x\in\left\{4;-1,6\right\}\)
làm giúp mình bài 1 với, mình cần gấp ( nếu rảnh làm hộ mình bài 2 cũng dc )
