\(=\dfrac{2}{\left|2-\sqrt{5}\right|}-\dfrac{2}{\left|2+\sqrt{5}\right|}=\dfrac{2}{\sqrt{5}-2}-\dfrac{2}{\sqrt{5}+2}\\ =\dfrac{2\sqrt{5}+4-2\sqrt{5}+4}{\left(\sqrt{5}-2\right)\left(\sqrt{5}+2\right)}=\dfrac{8}{1}=8\)
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