Question

Giúp em

Answer 1

\(\Leftrightarrow\)\(\left(2x-1\right)=\sqrt{27}:\sqrt{3}\)

\(\Leftrightarrow\)\(\left(2x-1\right)=3\)

\(\Leftrightarrow\)\(2x=4\)

\(\Leftrightarrow\)\(x=2\)

Vậy x=2

Answer 2

Ta có: \(\left(2x-1\right)\cdot\sqrt{3}=\sqrt{27}\)

\(\Leftrightarrow2x-1=3\)

\(\Leftrightarrow2x=4\)

hay x=2