Question

Giúp e bài 3 với ạ "(((

Answer 1

Tọa độ giao điểm là:

\(\left\{{}\begin{matrix}-x^2=3x-4\\y=-x^2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x^2=-3x+4\\y=-x^2\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x^2+3x-4=0\\y=-x^2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}\left(x+4\right)\left(x-1\right)=0\\y=-x^2\end{matrix}\right.\Leftrightarrow\left(x,y\right)\in\left\{\left(-4;-16\right);\left(1;-1\right)\right\}\)