ĐKXĐ:\(x\)≥0
PT⇔\(x+2\sqrt{x}-3\sqrt{x}-6=0\)⇔\(\sqrt{x}\left(\sqrt{x}+2\right)-3\left(\sqrt{x}+2\right)=0\)⇔\(\left(\sqrt{x}+2\right)\left(\sqrt{x}-3\right)=0\)
⇔\(\sqrt{x}=3\)vì\(\sqrt{x}+2\)>0
⇔\(x=9\)(thỏa mãn)
giải pt sau
1, \(\sqrt{5-2x}=6\)
2,\(\sqrt{2-x}-\sqrt{x+1}=0\)
3, \(\sqrt{4x^2+4x+1}=6\)
4,\(\sqrt{x^2-10x+25}=x-2\)
giải pt :\(\sqrt{x+3-4\sqrt{x-1}}+\sqrt{x+8+6\sqrt{x-1}}=5\)
giải pt sau
\(\sqrt{x+3}+\sqrt{6-x}-\sqrt{\left(x+3\right)\left(6-x\right)}=3\)
giải pt sau
a,x+y+z+4=2\(\sqrt{x-2}\)+4\(\sqrt{y-4}\)+6\(\sqrt{z-5}\)
Giải pt
\(5\sqrt[3]{x+1}+1\sqrt{x+2}+5\sqrt[3]{x+3}=0\)
giải pt:
\(\sqrt[3]{3-x}+\sqrt[3]{x-1}=0\)
Giải pt sau
a,\(^{x^2-6x+26=6\sqrt{2x+1}}\)
b,\(x^2+2x\sqrt{x-\dfrac{1}{x}}=3x+1\)
Giải pt, tìm x theo a, b (a > 0, b > 0)
\(\sqrt{a+b\sqrt{1-x}}=1+\sqrt{a-b\sqrt{1-x}}\)
giải pt
a) \(x+4\sqrt{7-x}=4\sqrt{x-1}+\sqrt{-x^2+8x-7}+1\)
b) \(x^4-16x^3+46x^2+144x+81=0\)
c) \(x-\sqrt{x-8}-3\sqrt{x}+1=0\)
d) \(x^2+\sqrt{x+5}=5\)
e) \(x+\sqrt{5+\sqrt{x-1}}=6\)
