Cho a, b, c >0 t/m: \(a^2\left(\dfrac{a}{c}+1\right)+b^2\left(\dfrac{b}{c}+1\right)=3\)

Tìm \(Min\) \(H=\dfrac{a+c}{b^3+2}+\dfrac{b+c}{a^3+2}-2\sqrt{a+b+c}\)

Cho \(a,b,c\ge0\) t/m: \(\left\{{}\begin{matrix}c\left(a+b\right)>0\\\left(a+b\right)^2+\left(b+c\right)^2+\left(c+a\right)^2\le6\end{matrix}\right.\)

Tìm Min: \(H=\left(a+b\right)\sqrt{1+\dfrac{3}{a+b^4}}+\sqrt{c^2+\dfrac{3}{c^2}}+\dfrac{\left(b+6\right)^2}{9\left(a+b+c\right)}\)

Cho \(\left\{{}\begin{matrix}x,y,z>0\\x\ge max\left\{y,z\right\}\end{matrix}\right.\). Tìm Min của:

\(M=\dfrac{x}{y}+2\sqrt{1+\dfrac{y}{z}}+3\sqrt[3]{1+\dfrac{z}{x}}\)

P/s: Đề trc bị sai nhé!