ĐKXĐ: \(-1\le x\le\frac{5}{3}\)
\(\Leftrightarrow6-2x+2\sqrt{-3x^2+2x+5}=3x^2-4x+4\)
\(\Leftrightarrow-3x^2+2x+5+2\sqrt{-3x^2+2x+5}-3=0\)
Đặt \(\sqrt{-3x^2+2x+5}=t\ge0\)
\(\Rightarrow t^2+2t-3=0\Rightarrow\left[{}\begin{matrix}t=1\\t=-3\left(l\right)\end{matrix}\right.\)
\(\Rightarrow\sqrt{-3x^2+2x+5}=1\)
\(\Leftrightarrow-3x^2+2x+4=0\)
\(\Leftrightarrow...\)
Giải pt : a) \(\sqrt[3]{x^2-1}+x=\sqrt{x^3-1}\)
b) \(\sqrt{2x^2+3x+5}+\sqrt{2x^2-3x+5}=3x\)
c) \(2x^2-11x+2x=3\sqrt[3]{4x-4}\)
Giải pt \(\sqrt{5x^2+4x}-\sqrt{x^2-3x-18}=5\sqrt{x}\)
Giải pt:
\(\left(3x^2+4x-4\right)\sqrt{x-1}=x\left(x^2-3x+3\right)\)
Giải pt:
\(x^2-4x+6=\sqrt{2x^2-5x+3}+\sqrt{-3x^2+9x-5}\)
Giải pt:
\(\sqrt[3]{3x+1}+\sqrt[3]{5-x}+\sqrt[3]{2x-9}-\sqrt[3]{4x-3}=0\)
Em cảm ơn ạ.
giải pt
\(\sqrt{4x+1}-\sqrt{3x-2}=\dfrac{x+3}{5}\)
1.Giai pt bang cach dat an phu :
a, 3x + 14 + 5\(\sqrt{x-2}\) = 7(\(\sqrt{x+1}+\sqrt{x^2-x-2}\) )
b, 7\(\sqrt{3x-7}\) +(4x-7)\(\sqrt{7-x}\) =32
giải pt : \(x^2-4x+12=4\sqrt{4-x}+\sqrt{3x+16}\)
Giải PT: \(\sqrt{\left(1+x^2\right)^3}-4x^3=1-3x^4\)
