\(x\ge0\)
\(\Leftrightarrow\sqrt{3+\sqrt{3+\sqrt{3+\sqrt{3+x}}}}=x\)
\(\Leftrightarrow\sqrt{3+\sqrt{3+\sqrt{3+\sqrt{3+\sqrt{3+\sqrt{3+x}}}}}}=x\)
\(\Leftrightarrow...\)
\(\Leftrightarrow\sqrt{3+\sqrt{3+...+\sqrt{3+x}}}=x\) (vô tận dấu căn)
\(\Leftrightarrow3+\sqrt{3+\sqrt{3+...+\sqrt{3+x}}}=x^2\)
\(\Leftrightarrow3+x=x^2\)
\(\Leftrightarrow x^2-x-3=0\Rightarrow\left[{}\begin{matrix}x=\frac{1+\sqrt{13}}{2}\\x=\frac{1-\sqrt{13}}{2}\left(l\right)\end{matrix}\right.\)