ĐKXĐ: \(x\ge\frac{3}{2}\)
\(\sqrt{2x-3+2\sqrt{2x-3}+1}+\sqrt{2x-3+8\sqrt{2x-3}+16}=5\)
\(\Leftrightarrow\sqrt{\left(\sqrt{2x-3}+1\right)^2}+\sqrt{\left(\sqrt{2x-3}+4\right)^2}=5\)
\(\Leftrightarrow\left|\sqrt{2x-3}+1\right|+\left|\sqrt{2x-3}+4\right|=5\)
\(\Leftrightarrow\sqrt{2x-3}+1+\sqrt{2x-3}+4=5\)
\(\Leftrightarrow2\sqrt{2x-3}=0\)
\(\Rightarrow2x-3=0\Rightarrow x=\frac{3}{2}\)