\(\frac{x+24}{18}\)=\(\frac{3x}{50}\)
\(\frac{x+24}{18}\)-\(\frac{3x}{50}\)=0
\(\frac{25\left(x+24\right)}{450}\)-\(\frac{27x}{450}\)=0
25x+600-27x=0
-2x=-600
x=300
Ta có:
\(\frac{x+24}{18}=\frac{3x}{50}\\ < =>\frac{25.\left(x+24\right)}{450}=\frac{9.3x}{450}\\ < =>25x+600=27x\\ < =>25x-27x=-600\\ < =>-2x=-600\\ =>x=\frac{-600}{-2}=300\)
\(\frac{x+24}{18}=\frac{3x}{50}\Leftrightarrow\frac{x}{18}+\frac{24}{18}=\frac{3x}{50}\Leftrightarrow\left(\frac{3}{50}-\frac{1}{18}\right)x=\frac{24}{18}\)
\(x=\frac{24}{18}:\frac{3.18-50}{50.18}=\frac{24.50.18}{18.4}=50.6=300\)
ta có: \(\frac{25\left(x+24\right)}{450}\)= \(\frac{9\cdot3x}{450}\)
(=) 25x + 600 = 27x
(=) 25x - 27x = -600
(=) -2x = -600
(=) x = \(\frac{-600}{-2}\)= 300
Vậy S = {300}
vì \(\frac{x+24}{18}\)=\(\frac{3x}{50}\)
nên (x+24)*50=18*3x
\(\Leftrightarrow\)50x+1200=54x
\(\Leftrightarrow\)50x-54x=-1200
\(\Leftrightarrow\)-4x=-1200
\(\Leftrightarrow\)x= \(\frac{-1200}{-4}\)=300
vây phương trình có 1 nghiệm S={300}
\(\frac{x+24}{18}=\frac{3x}{50}\)
\(\Leftrightarrow3x.18=\left(x+24\right)50\)
\(\Leftrightarrow54x=50x+1200\)
\(\Leftrightarrow54x-50x=1200\)
\(\Leftrightarrow4x=1200\Leftrightarrow x=300\)
\(\frac{x+24}{18}=\frac{3x}{50}\\ =\frac{25\left(x+24\right)}{18.25}=\frac{9.3x}{50.9}\\ =\frac{25x+600}{450}=\frac{27x}{450}\\ =25x+600+27x=0\\ =25x-27x=0-600\\ =-2x=-600\\ x=\frac{-600}{-2}=300\)
