Question

 Giai phương trình :

e ) || x - 2 | + 3| = 5

Answer 1

| | x - 2 |  + 3 | \(=5\)

Do \(\left|x-2\right|+3\ge3>0\)

\(\Rightarrow\left|x-2\right|+3=5\)

\(\Rightarrow\left|x-2\right|=2\)

\(\Rightarrow\left[\begin{array}{nghiempt}x-2=2\\x-2=-2\end{array}\right.\)

\(\Rightarrow\left[\begin{array}{nghiempt}x=4\\x=0\end{array}\right.\)

Vậy ............

Answer 2

| | x - 2| +3 | =5

\(\Rightarrow\left[\begin{array}{nghiempt}\left|x-2\right|+3=5\\\left|x-2\right|+3=-5\end{array}\right.\)

\(\Rightarrow\left[\begin{array}{nghiempt}\left|x-2\right|=2\\\left|x-2\right|=-8\left(l\right)\end{array}\right.\)

\(\Rightarrow\left|x-2\right|=2\)

\(\Rightarrow\left[\begin{array}{nghiempt}x-2=2\\x-2=-2\end{array}\right.\)

\(\Rightarrow\left[\begin{array}{nghiempt}x=4\\x=0\end{array}\right.\)

Vậy x=4 ; x=0