\(\dfrac{x+2}{98}+\dfrac{x+4}{96}=\dfrac{x+6}{94}+\dfrac{x+8}{92}\)
\(\Leftrightarrow\left(\dfrac{x+2}{98}+1\right)+\left(\dfrac{x+4}{96}+1\right)=\left(\dfrac{x+6}{94}+1\right)+\left(\dfrac{x+8}{92}+1\right)\)
\(\Leftrightarrow\dfrac{x+100}{98}+\dfrac{x+100}{96}-\dfrac{x+100}{94}+\dfrac{x+100}{92}=0\)
\(\Leftrightarrow\left(x+100\right)\left(\dfrac{1}{98}+\dfrac{1}{96}-\dfrac{1}{94}-\dfrac{1}{92}\right)=0\)
Vì : \(\dfrac{1}{98}+\dfrac{1}{96}-\dfrac{1}{94}-\dfrac{1}{92}\ne0\)
\(\Leftrightarrow x+100=0\Leftrightarrow x=-100\)
Vậy ...............
(x+2/98 +1)+(x+4/96 +1) = (x+6/94 +1)+(x+8/92 +1) x+2+98/98+ x+4+96/96 -x+6+94/94 -x+8+92/92 = 0 x+100/98 +x+100/96- x+100/94- x+100/92= 0 (x +100 ).(1/98 +1/96 -1/94 -1/92 ) = 0 vi` 1/98 >1/94 1/96 >1/92 nen 1/98 +1/96 >1/94 +1/92 hay 1/98 +1/96 -1/94 -1/92 > 0 Do do`: x +100=0 hay x = -100 cac bn thong cam nhe may tinh mk ko viet dau dc 
