ĐKXĐ: ...
\(\Leftrightarrow\left\{{}\begin{matrix}2\sqrt{4x-1}+\frac{2y}{2y+3}=2\\3\sqrt{4x-1}+\frac{3}{2y+3}=-1\end{matrix}\right.\)
\(\Rightarrow5\sqrt{4x-1}+\frac{2y+3}{2y+3}=1\)
\(\Leftrightarrow5\sqrt{4x-1}=0\Rightarrow4x-1=0\Rightarrow x=\frac{1}{4}\)
Thay vào pt trên:
\(\frac{y}{2y+3}=1\Leftrightarrow y=2y+3\Rightarrow y=-3\)