\(\left\{{}\begin{matrix}2x+3y=-2\\3x-2y=-3\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}6x-9y=-6\\6x-4y=-6\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}-5y=0\\2x+3y=-2\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}y=0\\2x+3.0=-3\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}y=0\\2x=-3\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}y=0\\x=-\frac{3}{2}\end{matrix}\right.\)
Vậy hệ phương trình có nghiệm duy nhất là \(\left(x;y\right)=\left(-\frac{3}{2};0\right)\)
