Question

Giải hệ phương trình:

\(\left\{{}\begin{matrix}\frac{x}{y}-\frac{x}{x+12}=1\\\frac{x}{x-12}-\frac{x}{y}=2\end{matrix}\right.\)

Answer 1

\(\left\{{}\begin{matrix}\frac{x}{y}-\frac{x}{x+12}=1\\-\frac{x}{y}+\frac{x}{x-12}=2\end{matrix}\right.\) \(\left(y\ne0;x\ne\pm12\right)\)

\(\Leftrightarrow\left\{{}\begin{matrix}\frac{24x}{x^2-144}=3\\y=\frac{x^2+12x}{12+2x}\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x=4+\sqrt{10}\\y=\frac{30+7\sqrt{10}}{10}\end{matrix}\right.\\\left\{{}\begin{matrix}x=4-\sqrt{10}\\y=\frac{30-7\sqrt{10}}{10}\end{matrix}\right.\end{matrix}\right.\)

Vậy....

Vì buồn ngủ quá nên ko bt có đúng không :3