Giải hệ phương trình: \(\left\{{}\begin{matrix}x^2y^2-2x+y^2=0\\2x^2+3=4x-y^3\end{matrix}\right.\)
Giải hệ
1) \(\left\{{}\begin{matrix}x-\dfrac{1}{x}=y-\dfrac{1}{y}\\2x^2-xy-1=0\end{matrix}\right.\)
2) \(\left\{{}\begin{matrix}y\left(4x^3+1\right)=3\\y^3\left(3x-1\right)=4\end{matrix}\right.\)
Giải hệ phương trình: \(\left\{{}\begin{matrix}x^2y^{2018}-2x+y^2=0\\2x^2-4x+3+y^{2019}=0\end{matrix}\right.\)
Giải hệ phương trình:
\(a,\left\{{}\begin{matrix}2x^3+x^2y+2x^2+xy+6=0\\x^2+3x+y=1\end{matrix}\right.\)
\(b,\left\{{}\begin{matrix}x^2=\left(2-y\right)\left(2+y\right)\\2x^3=\left(x+y\right)\left(4-xy\right)\end{matrix}\right.\)
\(c,\left\{{}\begin{matrix}\sqrt[3]{x+2y}=4-x-y\\\sqrt[3]{x+6}+\sqrt{2y}=2\end{matrix}\right.\)
Giải hệ phương trình :
1, \(\left\{{}\begin{matrix}\frac{2}{x}+\frac{3}{y-2}=4\\\frac{4}{x}+\frac{1}{y-2}=1\end{matrix}\right.\)
2 , \(\left\{{}\begin{matrix}\frac{2}{2x-y}-\frac{1}{x+y}=0\\\frac{3}{2x-y}-\frac{6}{x+y}=-1\end{matrix}\right.\)
3, \(\left\{{}\begin{matrix}5\left(x+2y\right)=3x-1\\2x+4=3\left(x-2y\right)-15\end{matrix}\right.\)
4, \(\left\{{}\begin{matrix}2x+y=7\\-x+4y=10\end{matrix}\right.\)
giải hpt:
1,\(\left\{{}\begin{matrix}x^2y^2-2x+y^2=0\\2x^2-4x+3+y^3=0\end{matrix}\right.\)
2. \(\left\{{}\begin{matrix}\left(x^2-xy\right)\left(xy-y^2\right)=25\\\sqrt{x^2-xy}+\sqrt{xy-y^2}=3\left(x-y\right)\end{matrix}\right.\)
1, giải hệ phương trình:\(\left\{{}\begin{matrix}y^3-2x^3+3x^2y-3xy^2=0\\x^2y^2-4x^2y-y^2-8x+8y+4=0\end{matrix}\right.\)
giải hệ pt:
(1) \(\left\{{}\begin{matrix}x^2-3xy+2y^2=0\\3x+y=6\end{matrix}\right.\)
(2)\(\left\{{}\begin{matrix}\dfrac{x-1}{2x+1}-\dfrac{y-2}{y+2}=1\\\dfrac{3x-3}{2x+1}+\dfrac{2y-4}{y+2}=3\end{matrix}\right.\)
(3)\(\left\{{}\begin{matrix}2\left(x+y\right)+\sqrt{x+1}=4\\x+y-3\sqrt{x+1}=-5\end{matrix}\right.\)
giải hệ phương trình
a) \(\left\{{}\begin{matrix}3x-2y+z=14\\2x+y-z=3\\z-2x=-5\end{matrix}\right.\)
b) \(\left\{{}\begin{matrix}x^2-y^2=4y+2x+3\\x^2+2x+y=0\end{matrix}\right.\)
c)\(\left\{{}\begin{matrix}\left|xy-4\right|=8-y^2\\xy=2+x^2\end{matrix}\right.\)