Đặt \(\left\{{}\begin{matrix}x\sqrt{y}=a\ge0\\y\sqrt{x}=b\ge0\end{matrix}\right.\)
\(\left\{{}\begin{matrix}2\left(a+1\right)^2=9a\\2\left(b+1\right)^2=9b\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}2a^2-5a+2=0\\2b^2-5b+2=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}\left(2a-1\right)\left(a-2\right)=0\\\left(2b-1\right)\left(b-2\right)=0\end{matrix}\right.\)
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