\(\dfrac{2x-1}{x+3}>2\)
\(\Leftrightarrow\dfrac{2x-1}{x+3}-2>0\)
\(\Leftrightarrow\dfrac{2x-1}{x+3}-\dfrac{2x+6}{x+3}>0\)
\(\Leftrightarrow\dfrac{-7}{x+3}>0\)
\(\Leftrightarrow x+3< 0\)
\(\Leftrightarrow x< -3\)
Ta có:
\(\dfrac{2x-1}{x+3}>2\)
\(\Rightarrow2x-1>2\left(x+3\right)\)
\(\Leftrightarrow2x-1>2x+6\)
\(\Leftrightarrow2x-2x>6+1\)
\(\Leftrightarrow0x>7\) ( loại)
Vậy bất pt vô nghiệm