\(\Leftrightarrow x^2-2x+3\left|x-1\right|-3< 0\)
\(\Leftrightarrow\left(x-1\right)^2+3\left|x-1\right|-3< 1\)
\(\left(x-1\right)^2\ge0\Rightarrow3\left|x-1\right|-3< 1\)\(\Leftrightarrow\left|x-1\right|-1< \frac{1}{3}\Leftrightarrow\left|x-1\right|< \frac{4}{3}\)
-Nếu x>=1, PT trở thành x-1<4/3 hay x<7/3
-Nếu x<1, PT trở thành -x+1<4/3 hay -x<1/3 hay x>1/3