Question

Giải  bất phương trình:

Answer 1

\(\Leftrightarrow\dfrac{2\left(x^2-1\right)+x\left(x+1\right)-x\left(x-1\right)}{x\left(x-1\right)\left(x+1\right)}\le0\)

\(\Leftrightarrow\dfrac{x^2+x-1}{x\left(x-1\right)\left(x+1\right)}\le0\)

\(\Rightarrow\left[{}\begin{matrix}x\le\dfrac{-1-\sqrt{5}}{2}\\-1< x< 0\\\dfrac{-1+\sqrt{5}}{2}\le x< 1\end{matrix}\right.\)