Question

Giải bất phương trình:

\(\dfrac{x-3}{2x+1}>0\)

Answer 1

\(\dfrac{x-3}{2x+1}>0\)

\(\Rightarrow\left\{{}\begin{matrix}x-3>0\\2x+1>0\end{matrix}\right.\)\(\Rightarrow\left\{{}\begin{matrix}x>3\\x>\dfrac{-1}{2}\end{matrix}\right.\)\(\Rightarrow x>3\)

\(\left\{{}\begin{matrix}x-3< 0\\2x+1< 0\end{matrix}\right.\)\(\Rightarrow\left\{{}\begin{matrix}x< 3\\x< \dfrac{-1}{2}\end{matrix}\right.\)\(\Rightarrow x< \dfrac{-1}{2}\)

Tập nghiệm :\(x>3\) \(;x< \dfrac{-1}{2}\)