\(\dfrac{x}{2^2}+\dfrac{x}{2^3}+\dfrac{x}{2^4}=\dfrac{x}{3^2}+\dfrac{x}{3^3}+\dfrac{x}{3^4}\)
\(\Leftrightarrow\dfrac{x}{2^2}+\dfrac{x}{2^3}+\dfrac{x}{2^4}-\dfrac{x}{3^2}-\dfrac{x}{3^3}-\dfrac{x}{3^4}=0\)
\(\Leftrightarrow x\left(\dfrac{1}{2^2}+\dfrac{1}{2^3}+\dfrac{1}{2^4}-\dfrac{1}{3^2}-\dfrac{1}{3^3}-\dfrac{1}{3^4}\right)=0\)
\(\Leftrightarrow x=0\)
Vậy x = 0