Question

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Answer 1

\(a,=\dfrac{1}{3}-\dfrac{4}{3}+\dfrac{2}{5}+\dfrac{12}{15}=-1+\dfrac{2}{5}+\dfrac{4}{5}=\dfrac{1}{5}\\ b,=\dfrac{2}{15}-1+\dfrac{1}{15}=\dfrac{1}{5}-1=-\dfrac{4}{5}\\ c,=\dfrac{9}{5}\left(-\dfrac{4}{13}+\dfrac{2}{7}+\dfrac{5}{7}-\dfrac{22}{13}\right)\\ =\dfrac{9}{5}\left(1-2\right)=-\dfrac{9}{5}\\ d,=0,25\left(-0,32\right)+2\cdot0,25\left(-0,16\right)\\ =-0,08-0,08=-0,16\)