\(\frac{x+2}{3}+\frac{3\left(2x-1\right)}{4}-\frac{5x-3}{9}=x+\frac{5}{12}\)
\(\Leftrightarrow12\left(x+2\right)+27\left(2x-1\right)-4\left(5x-3\right)=36x+15\)
\(\Leftrightarrow12x+24+54x-27-20x+12=36x+15\)
\(\Leftrightarrow12x+54x-20x-36x=15-24+27-12\)
\(10x=6\)
\(\Rightarrow x=\frac{6}{10}=\frac{3}{5}\)
\(\frac{x+2}{3}+\frac{3\left(2x-1\right)}{4}-\frac{5x-3}{9}=x+\frac{5}{12}\)
\(\Leftrightarrow\) \(\frac{12\left(x+2\right)}{36}+\frac{27\left(2x-1\right)}{36}-\frac{4\left(5x-3\right)}{36}=\frac{36x}{36}+\frac{15}{36}\)
\(\Leftrightarrow\) 12(x + 2) + 27(2x - 1) - 4(5x - 3) = 36x + 15
\(\Leftrightarrow\) 12x + 24 + 54x - 27 - 20x + 12 = 36x + 15
\(\Leftrightarrow\) 46x + 9 = 36x + 15
\(\Leftrightarrow\) 46x - 36x = 15 - 9
\(\Leftrightarrow\) 10x = 6
\(\Leftrightarrow\) x = \(\frac{3}{5}\)
Vậy S = {\(\frac{3}{5}\)}
Chúc bạn học tốt!
\(\frac{x+2}{3}+\frac{3\left(2x-1\right)}{4}-\frac{5x-3}{9}=x+\frac{5}{12}\)
\(\Leftrightarrow\frac{36\left(x+2\right)}{108}+\frac{81\left(2x-1\right)}{108}-\frac{12\left(5x-3\right)}{108}=\frac{108x}{108}+\frac{45}{108}\)
\(\Leftrightarrow36\left(x+2\right)+81\left(2x-1\right)-12\left(5x-3\right)=108x+45\)
Tự giải nốt nhé ( tớ cx k chắc đúng :> )
