\(\frac{x-1}{8}=\frac{2}{x-1}\)
\(\left(x-1\right)\left(x-1\right)=2\times8\)
\(\left(x-1\right)^2=16\)
\(\left(x-1\right)^2=\left(\pm4\right)^2\)
\(\left[\begin{array}{nghiempt}x-1=4\\x-1=-4\end{array}\right.\)
\(\left[\begin{array}{nghiempt}x=4+1\\x=-4+1\end{array}\right.\)
\(\left[\begin{array}{nghiempt}x=5\\x=-3\end{array}\right.\)
\(\frac{x-1}{8}=\frac{2}{x-1}\)
\(\Rightarrow\left(x-1\right)^2=2.8\)
\(\left(x-1\right)^2=16\)
\(\left(x-1\right)^2=4^2\)
\(x-1=\pm4\)
\(x\in\left\{5;-3\right\}\)
Vậy \(x\in\left\{5;-3\right\}\)
\(\frac{x-1}{8}=\frac{2}{x-1}\)
\(\Rightarrow\left(x-1\right)^2=16\)
\(\Rightarrow x-1=\pm4\)
+) \(x-1=4\Rightarrow x=5\)
+) \(x-1=-4\Rightarrow x=-3\)
Vậy x = 5 hoặc x = -3
\(\frac{x-1}{8}=\frac{2}{x-1}\Rightarrow\left(x-1\right)\left(x-1\right)=8\cdot2\)
\(\Rightarrow\left(x-1\right)^2=16\)
\(\Rightarrow x-1=\pm4\)
Nếu \(x-1=4\)
\(\Rightarrow x=5\)
Nếu \(x-1=-4\)
\(\Rightarrow x=-3\)
